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세 개의 구분자
def solution(myStr):
answer = []
myStr3 = []
myStr4 = []
myStr = myStr.split("a");
for i in myStr:
myStr2 = i.split("b")
for j in myStr2:
if j != "":
myStr3.append(j)
for i in myStr3:
test = i.split("c")
for j in test :
if j != "":
myStr4.append(j)
if len(myStr4) == 0 :
myStr4.append("EMPTY")
else :
return myStr4
return myStr4
배열의 원소만큼 추가하기
def solution(arr):
answer = []
for i in arr:
for j in range(0, i):
answer.append(i)
return answer
빈 배열에 추가, 삭제하기
def solution(arr, flag):
answer = []
for i, v in enumerate(flag):
if v :
for j in range(0, arr[i]*2):
answer.append(arr[i])
else:
for j in range(0, arr[i]):
answer.pop();
return answer
배열 만들기 6
def solution(arr):
answer = []
for i in range(len(arr)):
if len(answer) == 0:
answer.append(arr[i])
else :
if answer[-1] == arr[i]:
answer.pop();
else:
answer.append(arr[i])
if len(answer) == 0:
return [-1]
return answer
무작위로 K개의 수 뽑기
def solution(arr, k):
answer = []
for i in arr:
if i not in answer and len(answer) < k :
answer.append(i)
if len(answer) < k :
for i in range(0, k - len(answer)):
answer.append(-1)
return answer
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